So, f1 + f2 =
—- (ii)
Taking moment about the centre of mass G we get,
(f1 + f2)h + R1a – R2a = 0 [for rotational equilibrium net torque is zero]
Or, R2 – R1 =
(f1 + f2) =
——- (iii)
From equations (i) and (iii) we get, R1 =
(mg –
) and R2 =
(mg +
)
Therefore, the inner wheel will leave the ground when R1 = 0.
The limiting speed of the car not to overturn is v =
.