So, f_{1} + f_{2} = —- (ii)

Taking moment about the centre of mass G we get,

(f_{1} + f_{2})h + R_{1}a – R_{2}a = 0 [for rotational equilibrium net torque is zero]

Or, R_{2} – R_{1} = (f_{1} + f_{2}) = ——- (iii)

From equations (i) and (iii) we get, R_{1} = (mg – ) and R_{2} = (mg + )

Therefore, the inner wheel will leave the ground when R_{1} = 0.

The limiting speed of the car not to overturn is v = .