Prove: Let us consider
and
acting simultaneously on a particle be represented both in magnitude and direction by two sides OA and AC of
OAC taken in the same order.
is the resultant of
and
is represented by side OC.
So,
=
+ 
CN is the perpendicular on ON and θ is the angle between
and
.
In right-angled
ONC, OC2 = ON2 +NC2
Or, R2 = (OA + AN)2 + NC2
Or, R2 = OA2 + AN2 + 2OA.AN + NC2
Or, R2 = OA2 + AN2 + 2OA.ACcos
+ NC2
Or, R2 = OA2 + AC2 + 2OA.ACcos
[From right-angled
ANC,
=
so, AN = AC
and AN2+ NC2 = AC2]
R2 = P2 + Q2 + 2PQ
Let us consider creates angle with . Then from right-angled
ONC,
=
=
= 
Or,
=
[From right-angled
ANC,
=
].