Relation between object and image velocity:
1. When object is moving along the principal axis:
Let us consider, a point object is moving along the principal axis of a concave mirror of focal length f. At any instant the object distance is u and image distance is v. Using mirror formula we get, ——- (1).
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Differentiating equation (1) with respect to time we get, +
=
Or, – –
= 0 [f is constant so,
= 0]
Or, = –
—— (2)
Here (= vo) is the rate at which u is changing. This represents the object velocity with respect to the mirror. Similarly,
(= vi) represents the image velocity with respect to the mirror. If m is the magnification, then m = –
.
Therefore, = – m2
So, vi = – m2vo
The negative sign indicates that when u decreases v increase simultaneously.
2. When object is moving normal to the principal axis:
Let us considered, a point object O is at a distance u on the principle axis of a concave mirror. The corresponding image is formed at point I at a distance v from the pole of the mirror.
As the object is moving along a straight line perpendicular to the principal axis, then there is no change in the object and image distance.
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At any instant of time, the position of object is at point O/ at a distance x from the principal axis. At that time the corresponding image I/ is at a distance y from the principle axis of mirror.
Magnification m
Or, m =
Therefore, y = mx
Differentiating the equation with respect to time we get, = m
.
Here (= vo) represents the object velocity with respect to the mirror. Similarly,
(= vi) represents the image velocity with respect to the mirror.
Hence, vi = mvo.
Example: A point object is moving with velocity u at an angle with principle axis towards a stationary concave mirror of focal length f. Find the velocity of image when the object is at a distance of 1.5f from the mirror.
Object distance u = – 1.5f
Focal length of mirror is – f
Image distance v = ?
Using mirror formula we get,
Or,
Or, =
= –
v = – 3f
Magnification m = – = –
= – 2
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The component of velocity of object along principle axis is voh = ucos .
Velocity of object along perpendicular to principal axis is vov= usin .
Velocity of image along principle axis is vih = – m2voh = – 22ucos = – 4ucos
Velocity of image perpendicular to principal axis is viv = mvov = 2usin
Therefore, net velocity of image is vi = =
= 2u
.
If velocity of image creates angle with the principle axis, then, tan
=
=
= 0.5tan
.
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